Presence information quicken 2014 beta density oscillation theory formulation is said to form information density oscillation system may be stable.
Or more conditions, the presence of oscillation theory is expressed as: a system to maintain a constant information density may be stable.
Information density remains constant, the change means that the information density is 0, that dS = 0, or △ S = 0.
Why is the formation of information density oscillation system may be stable? As mentioned above, the identity of the oscillation system so that there is a certain range of the parties to quicken 2014 download coexist so that the return movement can be achieved, the system was in a steady state. The identity of the system performance of the oscillation from a quantitative point of view the information density oscillation, the oscillation density of the formation of information systems may be stable.
Directly, when forming the information density oscillations, the system's operating status greatly compressed, thus allowing the system to reach its stability.
Since the density of the formation of information systems may be stable oscillation, then the system remains constant information density may be stable.
Now do some specific analysis. For simplicity, assume that inertia is a constant, and people familiar with the information entropy formula as an example.
Information conversion balance and system stability
Information entropy formula is:
S =-ΣSi =-ΣPilnPi ⑴;
Where ΣPi = 1, (i = 1,2, ..., n)
Equilibrium conversion quicken 2014 release date in the information, the information entropy computing the n constant, but only the probability Pi (i = 1,2, ..., n) value is changed, the change in Si. If S is kept constant, the information entropy formula Si items remain in the conjugate change, that is when some of Si becomes large items, other items will be smaller Si, the S on the whole unchanged. Therefore, all Si items can be divided into three parts:
⑴ Si (i = 1,2, ..., k) is kept constant.
⑵ Si (i = k +1, k +2, ..., j) becomes large.
⑶ Si (i = j +1, j +2, ..., n) becomes small.
In the first case, the system will run on Si (i = 1,2, ..., k) to maintain a constant determined by the state, to the exclusion of Si (i = 1,2, ..., k) those states is not maintained constant .
For the second and third quicken 2014 release cases, the system state by the conjugate bound, that is, when some of the Si term becomes large, the other Si entry must be small, the system runs on a conjugated state constraints determined , to the exclusion of those outside conjugate bound state.
Therefore, the system will operate to maintain a constant state of Si and conjugate binding determined status, the system will stabilize at these conditions, to the exclusion of other states.
Conjugate bound to keep the system running in a particular state role in how much? An example can illustrate.
For example, two football games, the possibility of winning party is 4/5, B win possibility is 1/5, S = S (4/5, 1/5). Assumed that after the game, the two football entropy of a system constituted remain unchanged, which are only two possibilities:
⑴ Party remains the possibility of winning is 4/5, B win possibility is 1/5.
⑵ the possibility of change for the quicken 2014 Party to win is 1/5, B win possibility is 4/5.